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🍅 Не пройден линтинг или базовые тесты |
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🍅 Не пройден линтинг или базовые тесты |
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🍏 Пройдено тестов 9 из 9 |
bazhenova
reviewed
Nov 11, 2016
| off: function (event, context) { | ||
| console.info(event, context); | ||
| var eventsToOff = Object.keys(this._events).filter( | ||
| function (key) { |
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и еще эту строку можно к предыдущей приписать, так обычно пишут
bazhenova
reviewed
Nov 11, 2016
| function (key) { | ||
| return key === event || | ||
| (key.length > event.length && | ||
| key.substr(0, event.length + 1) === event + '.'); |
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вроде из условий
(key.length > event.length && key.substr(0, event.length + 1) === event + '.')достаточно написать последнее
bazhenova
reviewed
Nov 11, 2016
| key.substr(0, event.length + 1) === event + '.'); | ||
| } | ||
| ); | ||
| for (var i = 0; i < eventsToOff.length; i++) { |
bazhenova
reviewed
Nov 11, 2016
| emit: function (event) { | ||
| console.info(event); | ||
| var events = getAllEvents(event).reverse(); | ||
| for (var i = 0; i < events.length; i++) { |
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и тут вроде forEach хорошо впишется, тогда не придется создавать новую переменную строчкой ниже
bazhenova
reviewed
Nov 11, 2016
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| function getAllEvents(event) { | ||
| var splitted = event.split('.'); |
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Название не отражает, что лежит в переменной
bazhenova
reviewed
Nov 11, 2016
| */ | ||
| emit: function (event) { | ||
| console.info(event); | ||
| var events = getAllEvents(event).reverse(); |
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если ты сплитишь event, а потом реверсишь, то почему бы сразу не пойти с конца?
bazhenova
reviewed
Nov 11, 2016
| ); | ||
| for (var i = 0; i < eventsToOff.length; i++) { | ||
| this._events[eventsToOff[i]] = this._events[eventsToOff[i]].filter( | ||
| function (item) { |
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